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5x^2+25x-250=0
a = 5; b = 25; c = -250;
Δ = b2-4ac
Δ = 252-4·5·(-250)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-75}{2*5}=\frac{-100}{10} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+75}{2*5}=\frac{50}{10} =5 $
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